(k^2-k-20)/18

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Solution for (k^2-k-20)/18 equation: 


k in (-oo:+oo)

(k^2-k-20)/18 = 0

k^2-k-20 = 0

k^2-k-20 = 0

DELTA = (-1)^2-(-20*1*4)

DELTA = 81

DELTA > 0

k = (81^(1/2)+1)/(1*2) or k = (1-81^(1/2))/(1*2)

k = 5 or k = -4

(k+4)*(k-5) = 0

((k+4)*(k-5))/18 = 0

( k+4 )

k+4 = 0 // - 4

k = -4

( k-5 )

k-5 = 0 // + 5

k = 5

k in { -4, 5 }

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